1/2(10y-20)+3y=-25

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Solution for 1/2(10y-20)+3y=-25 equation: 



1/2(10y-20)+3y=-25

We move all terms to the left:

1/2(10y-20)+3y-(-25)=0



Domain of the equation: 2(10y-20)!=0

y∈R



We add all the numbers together, and all the variables

3y+1/2(10y-20)+25=0

We multiply all the terms by the denominator


3y*2(10y-20)+25*2(10y-20)+1=0

Wy multiply elements

6y^2(1+50y(1+1=0

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