-7(-2y+5)-2y=3(y-5)-5

Solution for -7(-2y+5)-2y=3(y-5)-5 equation:

-7(-2y+5)-2y=3(y-5)-5

We move all terms to the left:

-7(-2y+5)-2y-(3(y-5)-5)=0

We add all the numbers together, and all the variables

-2y-7(-2y+5)-(3(y-5)-5)=0

We multiply parentheses

-2y+14y-(3(y-5)-5)-35=0


We calculate terms in parentheses: -(3(y-5)-5), so:

3(y-5)-5

We multiply parentheses

3y-15-5

We add all the numbers together, and all the variables

3y-20

Back to the equation:

-(3y-20)


We add all the numbers together, and all the variables

12y-(3y-20)-35=0

We get rid of parentheses

12y-3y+20-35=0

We add all the numbers together, and all the variables

9y-15=0

We move all terms containing y to the left, all other terms to the right

9y=15

y=15/9

y=1+2/3