-6y+2(y+3)=-10

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Solution for -6y+2(y+3)=-10 equation: 



-6y+2(y+3)=-10

We move all terms to the left:

-6y+2(y+3)-(-10)=0

We add all the numbers together, and all the variables

-6y+2(y+3)+10=0

We multiply parentheses

-6y+2y+6+10=0

We add all the numbers together, and all the variables

-4y+16=0

We move all terms containing y to the left, all other terms to the right

-4y=-16

y=-16/-4

y=+4

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