29=11-3p+p2

Solution for 29=11-3p+p2 equation:

29=11-3p+p2

We move all terms to the left:

29-(11-3p+p2)=0

We add all the numbers together, and all the variables

-(-3p+p^2+11)+29=0

We get rid of parentheses

-p^2+3p-11+29=0

We add all the numbers together, and all the variables

-1p^2+3p+18=0

a = -1; b = 3; c = +18;
Δ = b2-4ac
Δ = 32-4·(-1)·18
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-9}{2*-1}=\frac{-12}{-2}
=+6
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+9}{2*-1}=\frac{6}{-2}
=-3
$