If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-6x^2+6x+120=0
a = -6; b = 6; c = +120;
Δ = b2-4ac
Δ = 62-4·(-6)·120
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-54}{2*-6}=\frac{-60}{-12} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+54}{2*-6}=\frac{48}{-12} =-4 $
| y=-6(2) | | 3(2a+3)-4a=-3 | | -25=0.5(10x-2)+3x | | -18-3x=-6x+24 | | 1/5y-4=-8 | | (4x-14)+(2x+18)=180 | | 53x+3297x-43=67(50x+34) | | 5/9(g+18(=1/5g+3 | | 53x+3297x-43=67(50x+34 | | 4w-16=12 | | -4x^2=-82 | | 3)2a+3)-4a=-3 | | 21+x=16 | | -4x=3x+13 | | 7x+5=-2+8 | | 9z+3z+12=0 | | x/8+12=-125 | | 2b+10=b-10 | | 6+x=180 | | -x-13=17-4x | | 14^5/7^3=2^v | | (x-2)(x+7)=(x+4)(x-3) | | x=82.5/2 | | F(x)=4x^2+x+3 | | 5g+7=3g+10 | | 3y=1/4y^2 | | x^+1=0 | | 3x-23=49-5x | | x+2x+28+x-8=180 | | F(x)=20x+6x-x^2 | | 20w-18w=-20 | | 3a(a+3)=0 |