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(x-2)(x+7)=(x+4)(x-3)
We move all terms to the left:
(x-2)(x+7)-((x+4)(x-3))=0
We multiply parentheses ..
(+x^2+7x-2x-14)-((x+4)(x-3))=0
We calculate terms in parentheses: -((x+4)(x-3)), so:We get rid of parentheses
(x+4)(x-3)
We multiply parentheses ..
(+x^2-3x+4x-12)
We get rid of parentheses
x^2-3x+4x-12
We add all the numbers together, and all the variables
x^2+x-12
Back to the equation:
-(x^2+x-12)
x^2-x^2+7x-2x-x-14+12=0
We add all the numbers together, and all the variables
4x-2=0
We move all terms containing x to the left, all other terms to the right
4x=2
x=2/4
x=1/2
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