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-6x^2+0x+216=0
We add all the numbers together, and all the variables
-6x^2+x+216=0
a = -6; b = 1; c = +216;
Δ = b2-4ac
Δ = 12-4·(-6)·216
Δ = 5185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{5185}}{2*-6}=\frac{-1-\sqrt{5185}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{5185}}{2*-6}=\frac{-1+\sqrt{5185}}{-12} $
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