7(y+5)=-3(3y-7)+8y

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Solution for 7(y+5)=-3(3y-7)+8y equation: 



7(y+5)=-3(3y-7)+8y

We move all terms to the left:

7(y+5)-(-3(3y-7)+8y)=0

We multiply parentheses

7y-(-3(3y-7)+8y)+35=0



We calculate terms in parentheses: -(-3(3y-7)+8y), so:

-3(3y-7)+8y

We add all the numbers together, and all the variables

8y-3(3y-7)

We multiply parentheses

8y-9y+21

We add all the numbers together, and all the variables

-1y+21

Back to the equation:

-(-1y+21)



We get rid of parentheses

7y+1y-21+35=0

We add all the numbers together, and all the variables

8y+14=0

We move all terms containing y to the left, all other terms to the right

8y=-14

y=-14/8

y=-1+3/4

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