-6x-2(x-3)=4(x+1)+2

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Solution for -6x-2(x-3)=4(x+1)+2 equation: 



-6x-2(x-3)=4(x+1)+2

We move all terms to the left:

-6x-2(x-3)-(4(x+1)+2)=0

We multiply parentheses

-6x-2x-(4(x+1)+2)+6=0



We calculate terms in parentheses: -(4(x+1)+2), so:

4(x+1)+2

We multiply parentheses

4x+4+2

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

-8x-(4x+6)+6=0

We get rid of parentheses

-8x-4x-6+6=0

We add all the numbers together, and all the variables

-12x=0

x=0/-12

x=0

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