-6x+5(4x-7)=-8(1-2x)-10

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Solution for -6x+5(4x-7)=-8(1-2x)-10 equation: 



-6x+5(4x-7)=-8(1-2x)-10

We move all terms to the left:

-6x+5(4x-7)-(-8(1-2x)-10)=0

We add all the numbers together, and all the variables

-6x+5(4x-7)-(-8(-2x+1)-10)=0

We multiply parentheses

-6x+20x-(-8(-2x+1)-10)-35=0



We calculate terms in parentheses: -(-8(-2x+1)-10), so:

-8(-2x+1)-10

We multiply parentheses

16x-8-10

We add all the numbers together, and all the variables

16x-18

Back to the equation:

-(16x-18)



We add all the numbers together, and all the variables

14x-(16x-18)-35=0

We get rid of parentheses

14x-16x+18-35=0

We add all the numbers together, and all the variables

-2x-17=0

We move all terms containing x to the left, all other terms to the right

-2x=17

x=17/-2

x=-8+1/2

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