5(4x+4)=6(3x-2)

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Solution for 5(4x+4)=6(3x-2) equation: 



5(4x+4)=6(3x-2)

We move all terms to the left:

5(4x+4)-(6(3x-2))=0

We multiply parentheses

20x-(6(3x-2))+20=0



We calculate terms in parentheses: -(6(3x-2)), so:

6(3x-2)

We multiply parentheses

18x-12

Back to the equation:

-(18x-12)



We get rid of parentheses

20x-18x+12+20=0

We add all the numbers together, and all the variables

2x+32=0

We move all terms containing x to the left, all other terms to the right

2x=-32

x=-32/2

x=-16

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