-6a+2a=4(6+5a)+3(1+a)

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Solution for -6a+2a=4(6+5a)+3(1+a) equation: 



-6a+2a=4(6+5a)+3(1+a)

We move all terms to the left:

-6a+2a-(4(6+5a)+3(1+a))=0

We add all the numbers together, and all the variables

-6a+2a-(4(5a+6)+3(a+1))=0

We add all the numbers together, and all the variables

-4a-(4(5a+6)+3(a+1))=0



We calculate terms in parentheses: -(4(5a+6)+3(a+1)), so:

4(5a+6)+3(a+1)

We multiply parentheses

20a+3a+24+3

We add all the numbers together, and all the variables

23a+27

Back to the equation:

-(23a+27)



We get rid of parentheses

-4a-23a-27=0

We add all the numbers together, and all the variables

-27a-27=0

We move all terms containing a to the left, all other terms to the right

-27a=27

a=27/-27

a=-1

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