-6=3(j+-5)

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Solution for -6=3(j+-5) equation: 



-6=3(j+-5)

We move all terms to the left:

-6-(3(j+-5))=0

We add all the numbers together, and all the variables

-(3(j-5))-6=0



We calculate terms in parentheses: -(3(j-5)), so:

3(j-5)

We multiply parentheses

3j-15

Back to the equation:

-(3j-15)



We get rid of parentheses

-3j+15-6=0

We add all the numbers together, and all the variables

-3j+9=0

We move all terms containing j to the left, all other terms to the right

-3j=-9

j=-9/-3

j=+3

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