x(3x-9)=(3x+8)(x-3)

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Solution for x(3x-9)=(3x+8)(x-3) equation: 



x(3x-9)=(3x+8)(x-3)

We move all terms to the left:

x(3x-9)-((3x+8)(x-3))=0

We multiply parentheses

3x^2-9x-((3x+8)(x-3))=0

We multiply parentheses ..

3x^2-((+3x^2-9x+8x-24))-9x=0



We calculate terms in parentheses: -((+3x^2-9x+8x-24)), so:

(+3x^2-9x+8x-24)

We get rid of parentheses

3x^2-9x+8x-24

We add all the numbers together, and all the variables

3x^2-1x-24

Back to the equation:

-(3x^2-1x-24)



We add all the numbers together, and all the variables

3x^2-9x-(3x^2-1x-24)=0

We get rid of parentheses

3x^2-3x^2-9x+1x+24=0

We add all the numbers together, and all the variables

-8x+24=0

We move all terms containing x to the left, all other terms to the right

-8x=-24

x=-24/-8

x=+3

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