-65y(y-5)=y+-25

Solution for -65y(y-5)=y+-25 equation:

-65y(y-5)=y+-25

We move all terms to the left:

-65y(y-5)-(y+-25)=0

We add all the numbers together, and all the variables

-65y(y-5)-(y-25)=0

We multiply parentheses

-65y^2+325y-(y-25)=0

We get rid of parentheses

-65y^2+325y-y+25=0

We add all the numbers together, and all the variables

-65y^2+324y+25=0

a = -65; b = 324; c = +25;
Δ = b2-4ac
Δ = 3242-4·(-65)·25
Δ = 111476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{111476}=\sqrt{3844*29}=\sqrt{3844}*\sqrt{29}=62\sqrt{29}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(324)-62\sqrt{29}}{2*-65}=\frac{-324-62\sqrt{29}}{-130}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(324)+62\sqrt{29}}{2*-65}=\frac{-324+62\sqrt{29}}{-130}
$