(2+3i)*(8-7i)=0

Solution for (2+3i)*(8-7i)=0 equation:

(2+3i)(8-7i)=0

We add all the numbers together, and all the variables

(3i+2)(-7i+8)=0

We multiply parentheses ..

(-21i^2+24i-14i+16)=0

We get rid of parentheses

-21i^2+24i-14i+16=0

We add all the numbers together, and all the variables

-21i^2+10i+16=0

a = -21; b = 10; c = +16;
Δ = b2-4ac
Δ = 102-4·(-21)·16
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-38}{2*-21}=\frac{-48}{-42}
=1+1/7
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+38}{2*-21}=\frac{28}{-42}
=-2/3
$