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-6/1x+-7=-5-x
We move all terms to the left:
-6/1x+-7-(-5-x)=0
Domain of the equation: 1x!=0We add all the numbers together, and all the variables
x∈R
-6/1x-(-1x-5)-7+=0
We add all the numbers together, and all the variables
-6/1x-(-1x-5)=0
We get rid of parentheses
-6/1x+1x+5=0
We multiply all the terms by the denominator
1x*1x+5*1x-6=0
Wy multiply elements
x^2+5x-6=0
a = 1; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·1·(-6)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*1}=\frac{-12}{2} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*1}=\frac{2}{2} =1 $
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