16=1/6(-12)+b

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Solution for 16=1/6(-12)+b equation: 



16=1/6(-12)+b

We move all terms to the left:

16-(1/6(-12)+b)=0



Domain of the equation: 6(-12)+b)!=0

b∈R



We multiply all the terms by the denominator


-(1+16*6(-12)+b)=0



We calculate terms in parentheses: -(1+16*6(-12)+b), so:

1+16*6(-12)+b

determiningTheFunctionDomain
b+1+16*6(-12)

We add all the numbers together, and all the variables

b-1151

Back to the equation:

-(b-1151)



We get rid of parentheses

-b+1151=0

We add all the numbers together, and all the variables

-1b+1151=0

We move all terms containing b to the left, all other terms to the right

-b=-1151

b=-1151/-1

b=+1151

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