-6/(z-4)=12

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Solution for -6/(z-4)=12 equation: 



-6/(z-4)=12

We move all terms to the left:

-6/(z-4)-(12)=0



Domain of the equation: (z-4)!=0

We move all terms containing z to the left, all other terms to the right

z!=4

z∈R



We multiply all the terms by the denominator


-12*(z-4)-6=0

We multiply parentheses

-12z+48-6=0

We add all the numbers together, and all the variables

-12z+42=0

We move all terms containing z to the left, all other terms to the right

-12z=-42

z=-42/-12

z=3+1/2

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