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12(y+3)=6(2y+4)
We move all terms to the left:
12(y+3)-(6(2y+4))=0
We multiply parentheses
12y-(6(2y+4))+36=0
We calculate terms in parentheses: -(6(2y+4)), so:We get rid of parentheses
6(2y+4)
We multiply parentheses
12y+24
Back to the equation:
-(12y+24)
12y-12y-24+36=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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