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-6-5x=2x(x+4)
We move all terms to the left:
-6-5x-(2x(x+4))=0
We calculate terms in parentheses: -(2x(x+4)), so:We get rid of parentheses
2x(x+4)
We multiply parentheses
2x^2+8x
Back to the equation:
-(2x^2+8x)
-2x^2-5x-8x-6=0
We add all the numbers together, and all the variables
-2x^2-13x-6=0
a = -2; b = -13; c = -6;
Δ = b2-4ac
Δ = -132-4·(-2)·(-6)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-11}{2*-2}=\frac{2}{-4} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+11}{2*-2}=\frac{24}{-4} =-6 $
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