-2(3z+1)=28

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Solution for -2(3z+1)=28 equation: 



-2(3z+1)=28

We move all terms to the left:

-2(3z+1)-(28)=0

We multiply parentheses

-6z-2-28=0

We add all the numbers together, and all the variables

-6z-30=0

We move all terms containing z to the left, all other terms to the right

-6z=30

z=30/-6

z=-5

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