-6(z+2)+3(4z-6)=5(z-4)+13

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Solution for -6(z+2)+3(4z-6)=5(z-4)+13 equation: 



-6(z+2)+3(4z-6)=5(z-4)+13

We move all terms to the left:

-6(z+2)+3(4z-6)-(5(z-4)+13)=0

We multiply parentheses

-6z+12z-(5(z-4)+13)-12-18=0



We calculate terms in parentheses: -(5(z-4)+13), so:

5(z-4)+13

We multiply parentheses

5z-20+13

We add all the numbers together, and all the variables

5z-7

Back to the equation:

-(5z-7)



We add all the numbers together, and all the variables

6z-(5z-7)-30=0

We get rid of parentheses

6z-5z+7-30=0

We add all the numbers together, and all the variables

z-23=0

We move all terms containing z to the left, all other terms to the right

z=23

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