X+(2x-40)+(3x-50)=15002

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Solution for X+(2x-40)+(3x-50)=15002 equation: 



X+(2X-40)+(3X-50)=15002

We move all terms to the left:

X+(2X-40)+(3X-50)-(15002)=0

We get rid of parentheses

X+2X+3X-40-50-15002=0

We add all the numbers together, and all the variables

6X-15092=0

We move all terms containing X to the left, all other terms to the right

6X=15092

X=15092/6

X=2515+1/3

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