-6(y+1)=y-3+3(3y+3)

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Solution for -6(y+1)=y-3+3(3y+3) equation: 



-6(y+1)=y-3+3(3y+3)

We move all terms to the left:

-6(y+1)-(y-3+3(3y+3))=0

We multiply parentheses

-6y-(y-3+3(3y+3))-6=0



We calculate terms in parentheses: -(y-3+3(3y+3)), so:

y-3+3(3y+3)

determiningTheFunctionDomain
y+3(3y+3)-3

We multiply parentheses

y+9y+9-3

We add all the numbers together, and all the variables

10y+6

Back to the equation:

-(10y+6)



We get rid of parentheses

-6y-10y-6-6=0

We add all the numbers together, and all the variables

-16y-12=0

We move all terms containing y to the left, all other terms to the right

-16y=12

y=12/-16

y=-3/4

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