-2(u+8)=4u-3+2(3u+1)

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Solution for -2(u+8)=4u-3+2(3u+1) equation: 



-2(u+8)=4u-3+2(3u+1)

We move all terms to the left:

-2(u+8)-(4u-3+2(3u+1))=0

We multiply parentheses

-2u-(4u-3+2(3u+1))-16=0



We calculate terms in parentheses: -(4u-3+2(3u+1)), so:

4u-3+2(3u+1)

determiningTheFunctionDomain
4u+2(3u+1)-3

We multiply parentheses

4u+6u+2-3

We add all the numbers together, and all the variables

10u-1

Back to the equation:

-(10u-1)



We get rid of parentheses

-2u-10u+1-16=0

We add all the numbers together, and all the variables

-12u-15=0

We move all terms containing u to the left, all other terms to the right

-12u=15

u=15/-12

u=-1+1/4

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