-6(y+1)=2y-3+2(5y+3)

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Solution for -6(y+1)=2y-3+2(5y+3) equation: 



-6(y+1)=2y-3+2(5y+3)

We move all terms to the left:

-6(y+1)-(2y-3+2(5y+3))=0

We multiply parentheses

-6y-(2y-3+2(5y+3))-6=0



We calculate terms in parentheses: -(2y-3+2(5y+3)), so:

2y-3+2(5y+3)

determiningTheFunctionDomain
2y+2(5y+3)-3

We multiply parentheses

2y+10y+6-3

We add all the numbers together, and all the variables

12y+3

Back to the equation:

-(12y+3)



We get rid of parentheses

-6y-12y-3-6=0

We add all the numbers together, and all the variables

-18y-9=0

We move all terms containing y to the left, all other terms to the right

-18y=9

y=9/-18

y=-1/2

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