-6(y+1)=2y-3+2(5y+2)

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Solution for -6(y+1)=2y-3+2(5y+2) equation: 



-6(y+1)=2y-3+2(5y+2)

We move all terms to the left:

-6(y+1)-(2y-3+2(5y+2))=0

We multiply parentheses

-6y-(2y-3+2(5y+2))-6=0



We calculate terms in parentheses: -(2y-3+2(5y+2)), so:

2y-3+2(5y+2)

determiningTheFunctionDomain
2y+2(5y+2)-3

We multiply parentheses

2y+10y+4-3

We add all the numbers together, and all the variables

12y+1

Back to the equation:

-(12y+1)



We get rid of parentheses

-6y-12y-1-6=0

We add all the numbers together, and all the variables

-18y-7=0

We move all terms containing y to the left, all other terms to the right

-18y=7

y=7/-18

y=-7/18

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