-6(x-2)+4(3+6x)=-36

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Solution for -6(x-2)+4(3+6x)=-36 equation:



-6(x-2)+4(3+6x)=-36
We move all terms to the left:
-6(x-2)+4(3+6x)-(-36)=0
We add all the numbers together, and all the variables
-6(x-2)+4(6x+3)-(-36)=0
We add all the numbers together, and all the variables
-6(x-2)+4(6x+3)+36=0
We multiply parentheses
-6x+24x+12+12+36=0
We add all the numbers together, and all the variables
18x+60=0
We move all terms containing x to the left, all other terms to the right
18x=-60
x=-60/18
x=-3+1/3

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