1/3(-12k+39)=8+10k

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Solution for 1/3(-12k+39)=8+10k equation: 



1/3(-12k+39)=8+10k

We move all terms to the left:

1/3(-12k+39)-(8+10k)=0



Domain of the equation: 3(-12k+39)!=0

k∈R



We add all the numbers together, and all the variables

1/3(-12k+39)-(10k+8)=0

We get rid of parentheses

1/3(-12k+39)-10k-8=0

We multiply all the terms by the denominator


-10k*3(-12k+39)-8*3(-12k+39)+1=0

Wy multiply elements

-30k^2(--24k(-+1=0

We use the square of the difference formula

-30k^2(+24k(-1=0

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