-6(v+1)=2(1+3v)-7

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Solution for -6(v+1)=2(1+3v)-7 equation: 



-6(v+1)=2(1+3v)-7

We move all terms to the left:

-6(v+1)-(2(1+3v)-7)=0

We add all the numbers together, and all the variables

-6(v+1)-(2(3v+1)-7)=0

We multiply parentheses

-6v-(2(3v+1)-7)-6=0



We calculate terms in parentheses: -(2(3v+1)-7), so:

2(3v+1)-7

We multiply parentheses

6v+2-7

We add all the numbers together, and all the variables

6v-5

Back to the equation:

-(6v-5)



We get rid of parentheses

-6v-6v+5-6=0

We add all the numbers together, and all the variables

-12v-1=0

We move all terms containing v to the left, all other terms to the right

-12v=1

v=1/-12

v=-1/12

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