(3x+8)=(12x-28)

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Solution for (3x+8)=(12x-28) equation: 



(3x+8)=(12x-28)

We move all terms to the left:

(3x+8)-((12x-28))=0

We get rid of parentheses

3x-((12x-28))+8=0



We calculate terms in parentheses: -((12x-28)), so:

(12x-28)

We get rid of parentheses

12x-28

Back to the equation:

-(12x-28)



We get rid of parentheses

3x-12x+28+8=0

We add all the numbers together, and all the variables

-9x+36=0

We move all terms containing x to the left, all other terms to the right

-9x=-36

x=-36/-9

x=+4

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