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-6(v+1)+8v=(v-3)
We move all terms to the left:
-6(v+1)+8v-((v-3))=0
We add all the numbers together, and all the variables
8v-6(v+1)-((v-3))=0
We multiply parentheses
8v-6v-((v-3))-6=0
We calculate terms in parentheses: -((v-3)), so:We add all the numbers together, and all the variables
(v-3)
We get rid of parentheses
v-3
Back to the equation:
-(v-3)
2v-(v-3)-6=0
We get rid of parentheses
2v-v+3-6=0
We add all the numbers together, and all the variables
v-3=0
We move all terms containing v to the left, all other terms to the right
v=3
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