8(2+3z)+1=2-10(z+1)

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Solution for 8(2+3z)+1=2-10(z+1) equation:



8(2+3z)+1=2-10(z+1)
We move all terms to the left:
8(2+3z)+1-(2-10(z+1))=0
We add all the numbers together, and all the variables
8(3z+2)-(2-10(z+1))+1=0
We multiply parentheses
24z-(2-10(z+1))+16+1=0
We calculate terms in parentheses: -(2-10(z+1)), so:
2-10(z+1)
determiningTheFunctionDomain -10(z+1)+2
We multiply parentheses
-10z-10+2
We add all the numbers together, and all the variables
-10z-8
Back to the equation:
-(-10z-8)
We add all the numbers together, and all the variables
24z-(-10z-8)+17=0
We get rid of parentheses
24z+10z+8+17=0
We add all the numbers together, and all the variables
34z+25=0
We move all terms containing z to the left, all other terms to the right
34z=-25
z=-25/34
z=-25/34

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