-6(n-1)+3n=2(n-2)

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Solution for -6(n-1)+3n=2(n-2) equation:



-6(n-1)+3n=2(n-2)
We move all terms to the left:
-6(n-1)+3n-(2(n-2))=0
We add all the numbers together, and all the variables
3n-6(n-1)-(2(n-2))=0
We multiply parentheses
3n-6n-(2(n-2))+6=0
We calculate terms in parentheses: -(2(n-2)), so:
2(n-2)
We multiply parentheses
2n-4
Back to the equation:
-(2n-4)
We add all the numbers together, and all the variables
-3n-(2n-4)+6=0
We get rid of parentheses
-3n-2n+4+6=0
We add all the numbers together, and all the variables
-5n+10=0
We move all terms containing n to the left, all other terms to the right
-5n=-10
n=-10/-5
n=+2

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