-6(k-3)=27+3k

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Solution for -6(k-3)=27+3k equation: 



-6(k-3)=27+3k

We move all terms to the left:

-6(k-3)-(27+3k)=0

We add all the numbers together, and all the variables

-6(k-3)-(3k+27)=0

We multiply parentheses

-6k-(3k+27)+18=0

We get rid of parentheses

-6k-3k-27+18=0

We add all the numbers together, and all the variables

-9k-9=0

We move all terms containing k to the left, all other terms to the right

-9k=9

k=9/-9

k=-1

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