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-6(b+1)+8b=2(b-3)
We move all terms to the left:
-6(b+1)+8b-(2(b-3))=0
We add all the numbers together, and all the variables
8b-6(b+1)-(2(b-3))=0
We multiply parentheses
8b-6b-(2(b-3))-6=0
We calculate terms in parentheses: -(2(b-3)), so:We add all the numbers together, and all the variables
2(b-3)
We multiply parentheses
2b-6
Back to the equation:
-(2b-6)
2b-(2b-6)-6=0
We get rid of parentheses
2b-2b+6-6=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0
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