3(2x+1)+3x=33(2x+1)+3x=39

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Solution for 3(2x+1)+3x=33(2x+1)+3x=39 equation: 



3(2x+1)+3x=33(2x+1)+3x=39

We move all terms to the left:

3(2x+1)+3x-(33(2x+1)+3x)=0

We add all the numbers together, and all the variables

3x+3(2x+1)-(33(2x+1)+3x)=0

We multiply parentheses

3x+6x-(33(2x+1)+3x)+3=0



We calculate terms in parentheses: -(33(2x+1)+3x), so:

33(2x+1)+3x

We add all the numbers together, and all the variables

3x+33(2x+1)

We multiply parentheses

3x+66x+33

We add all the numbers together, and all the variables

69x+33

Back to the equation:

-(69x+33)



We add all the numbers together, and all the variables

9x-(69x+33)+3=0

We get rid of parentheses

9x-69x-33+3=0

We add all the numbers together, and all the variables

-60x-30=0

We move all terms containing x to the left, all other terms to the right

-60x=30

x=30/-60

x=-1/2

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