-6(3y-4)+4y=2(y+6)

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Solution for -6(3y-4)+4y=2(y+6) equation: 



-6(3y-4)+4y=2(y+6)

We move all terms to the left:

-6(3y-4)+4y-(2(y+6))=0

We add all the numbers together, and all the variables

4y-6(3y-4)-(2(y+6))=0

We multiply parentheses

4y-18y-(2(y+6))+24=0



We calculate terms in parentheses: -(2(y+6)), so:

2(y+6)

We multiply parentheses

2y+12

Back to the equation:

-(2y+12)



We add all the numbers together, and all the variables

-14y-(2y+12)+24=0

We get rid of parentheses

-14y-2y-12+24=0

We add all the numbers together, and all the variables

-16y+12=0

We move all terms containing y to the left, all other terms to the right

-16y=-12

y=-12/-16

y=3/4

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