-6(3y+10)=12

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Solution for -6(3y+10)=12 equation: 



-6(3y+10)=12

We move all terms to the left:

-6(3y+10)-(12)=0

We multiply parentheses

-18y-60-12=0

We add all the numbers together, and all the variables

-18y-72=0

We move all terms containing y to the left, all other terms to the right

-18y=72

y=72/-18

y=-4

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