9c-2(3+c)=15

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Solution for 9c-2(3+c)=15 equation: 



9c-2(3+c)=15

We move all terms to the left:

9c-2(3+c)-(15)=0

We add all the numbers together, and all the variables

9c-2(c+3)-15=0

We multiply parentheses

9c-2c-6-15=0

We add all the numbers together, and all the variables

7c-21=0

We move all terms containing c to the left, all other terms to the right

7c=21

c=21/7

c=3

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