-6(3+2k)=3(-3k+5)

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Solution for -6(3+2k)=3(-3k+5) equation: 



-6(3+2k)=3(-3k+5)

We move all terms to the left:

-6(3+2k)-(3(-3k+5))=0

We add all the numbers together, and all the variables

-6(2k+3)-(3(-3k+5))=0

We multiply parentheses

-12k-(3(-3k+5))-18=0



We calculate terms in parentheses: -(3(-3k+5)), so:

3(-3k+5)

We multiply parentheses

-9k+15

Back to the equation:

-(-9k+15)



We get rid of parentheses

-12k+9k-15-18=0

We add all the numbers together, and all the variables

-3k-33=0

We move all terms containing k to the left, all other terms to the right

-3k=33

k=33/-3

k=-11

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