5(a+1)=8-(a-3)

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Solution for 5(a+1)=8-(a-3) equation: 



5(a+1)=8-(a-3)

We move all terms to the left:

5(a+1)-(8-(a-3))=0

We multiply parentheses

5a-(8-(a-3))+5=0



We calculate terms in parentheses: -(8-(a-3)), so:

8-(a-3)

determiningTheFunctionDomain
-(a-3)+8

We get rid of parentheses

-a+3+8

We add all the numbers together, and all the variables

-1a+11

Back to the equation:

-(-1a+11)



We get rid of parentheses

5a+1a-11+5=0

We add all the numbers together, and all the variables

6a-6=0

We move all terms containing a to the left, all other terms to the right

6a=6

a=6/6

a=1

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