-6(2u-2)+6u=9+3(2u-1)

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Solution for -6(2u-2)+6u=9+3(2u-1) equation: 



-6(2u-2)+6u=9+3(2u-1)

We move all terms to the left:

-6(2u-2)+6u-(9+3(2u-1))=0

We add all the numbers together, and all the variables

6u-6(2u-2)-(9+3(2u-1))=0

We multiply parentheses

6u-12u-(9+3(2u-1))+12=0



We calculate terms in parentheses: -(9+3(2u-1)), so:

9+3(2u-1)

determiningTheFunctionDomain
3(2u-1)+9

We multiply parentheses

6u-3+9

We add all the numbers together, and all the variables

6u+6

Back to the equation:

-(6u+6)



We add all the numbers together, and all the variables

-6u-(6u+6)+12=0

We get rid of parentheses

-6u-6u-6+12=0

We add all the numbers together, and all the variables

-12u+6=0

We move all terms containing u to the left, all other terms to the right

-12u=-6

u=-6/-12

u=1/2

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