-4(x+1)+7x=4(x+1)-5

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Solution for -4(x+1)+7x=4(x+1)-5 equation: 



-4(x+1)+7x=4(x+1)-5

We move all terms to the left:

-4(x+1)+7x-(4(x+1)-5)=0

We add all the numbers together, and all the variables

7x-4(x+1)-(4(x+1)-5)=0

We multiply parentheses

7x-4x-(4(x+1)-5)-4=0



We calculate terms in parentheses: -(4(x+1)-5), so:

4(x+1)-5

We multiply parentheses

4x+4-5

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We add all the numbers together, and all the variables

3x-(4x-1)-4=0

We get rid of parentheses

3x-4x+1-4=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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