-6(1v+1)+8v=2(1v-3)

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Solution for -6(1v+1)+8v=2(1v-3) equation: 



-6(1v+1)+8v=2(1v-3)

We move all terms to the left:

-6(1v+1)+8v-(2(1v-3))=0

We add all the numbers together, and all the variables

-6(v+1)+8v-(2(v-3))=0

We add all the numbers together, and all the variables

8v-6(v+1)-(2(v-3))=0

We multiply parentheses

8v-6v-(2(v-3))-6=0



We calculate terms in parentheses: -(2(v-3)), so:

2(v-3)

We multiply parentheses

2v-6

Back to the equation:

-(2v-6)



We add all the numbers together, and all the variables

2v-(2v-6)-6=0

We get rid of parentheses

2v-2v+6-6=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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