(7x+5)/6=(3x-10)/5

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Solution for (7x+5)/6=(3x-10)/5 equation: 



(7x+5)/6=(3x-10)/5

We move all terms to the left:

(7x+5)/6-((3x-10)/5)=0

We calculate fractions


7x/()+(-((3x-10)*6)/()=0



We calculate terms in parentheses: +(-((3x-10)*6)/(), so:

-((3x-10)*6)/(

We multiply all the terms by the denominator


-((3x-10)*6)



We calculate terms in parentheses: -((3x-10)*6), so:

(3x-10)*6

We multiply parentheses

18x-60

Back to the equation:

-(18x-60)



We get rid of parentheses

-18x+60

Back to the equation:

+(-18x+60)



We get rid of parentheses

7x/()-18x+60=0

We multiply all the terms by the denominator


7x-18x*()+60*()=0

We add all the numbers together, and all the variables

7x-18x*()=0

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