-6(1+8x)=40-2x

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Solution for -6(1+8x)=40-2x equation: 



-6(1+8x)=40-2x

We move all terms to the left:

-6(1+8x)-(40-2x)=0

We add all the numbers together, and all the variables

-6(8x+1)-(-2x+40)=0

We multiply parentheses

-48x-(-2x+40)-6=0

We get rid of parentheses

-48x+2x-40-6=0

We add all the numbers together, and all the variables

-46x-46=0

We move all terms containing x to the left, all other terms to the right

-46x=46

x=46/-46

x=-1

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