(2)/(3)x=9-2((1)/(3)+3)

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Solution for (2)/(3)x=9-2((1)/(3)+3) equation: 



(2)/(3)x=9-2((1)/(3)+3)

We move all terms to the left:

(2)/(3)x-(9-2((1)/(3)+3))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We calculate fractions


()/9x+(-(9-2(1*3x)/9x=0

We add all the numbers together, and all the variables

()/9x+(-(9-2(+1*3x)/9x=0

We multiply all the terms by the denominator


(-(9-2(+1*3x)+()=0



We calculate terms in parentheses: +(-(9-2(+1*3x)+(), so:

-(9-2(+1*3x)+(





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-(9-2(+1*3x)+(





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-(9-2(+1*3x)+(





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