4n-6=(3(n-2))+58

Solution for 4n-6=(3(n-2))+58 equation:

4n-6=(3(n-2))+58

We move all terms to the left:

4n-6-((3(n-2))+58)=0


We calculate terms in parentheses: -((3(n-2))+58), so:

(3(n-2))+58


We calculate terms in parentheses: +(3(n-2)), so:

3(n-2)

We multiply parentheses

3n-6

Back to the equation:

+(3n-6)


We get rid of parentheses

3n-6+58

We add all the numbers together, and all the variables

3n+52

Back to the equation:

-(3n+52)


We get rid of parentheses

4n-3n-52-6=0

We add all the numbers together, and all the variables

n-58=0

We move all terms containing n to the left, all other terms to the right

n=58